This is a Dark Detecting LED light schematic I found here
Few Questions(As I'm new to electronics),
- Can I use this circuit with a 6v input ?
- When there is light on the LDR(Photo-resistor) curent will flow
through R2 and PH1 (LDR) right ? So when there is light power will
be wasted ? If so, how many Ma(Mili-amperes)? - What to change if I want to use a 5v led(70ma @ 5v while input is 6v as stated in question No.1. It's 4Leds removed from a torchlight) ? (The resistor values)
Edit : I edited the questions after "Peter Bennett" answered.
Edit: I (Peter Bennett) edited my answer after the OP's edit.
Best Answer
I expect that the supply voltage is not very critical - 6 volts should be fine.
You can determine using Ohm's Law, that the maximum current through R2 will be about .05 mA.
An LED advertised as "5 volt" will be a bare LED with a suitable resistor or current limiting circuit so that it can be operated from 5 volts with no additional current limiting components. (I believe the highest voltage bare LEDs are blue (or white, which is just blue with a white phosphor) which have a forward voltage of 3.0 - 3.5 volts)