I don't understand how to calculate the voltage that should enter the inverting terminal of the amplifier[V-]
Could you help me to find out how this circuit works and why the output, when Vin is zero, will be 1.6V?
Note that \$R_1\$ and \$R_2\$ are a simple voltage divider, so we could remove those resistors to keep the circuit simple.
$$R_3 = 1\text{k}\Omega$$
$$R_4 = 3\text{k}\Omega$$
$$R_5 = 1.5\text{k}\Omega$$
CV+ (Positive supply voltage of the op amp) = +5V
CV- (Negative supply voltage of the op amp) = -5V
Best Answer
Feed back will try and make the two inputs the same. So the inverting input is also at zero volts. The negative voltage (CV-) is sucking 5/3k = 1.66mA from that node. The only place that current can come from is the opamp output. You need 1.66 mA flowing through R3... and that gives 1.66V on the opamp output. (No current can come from R5 because both sides are at zero volts... that is only true when Vin is zero.)