I am lost here, I was wondering what voltages do I have to include in the equation that is asked for both v1 and v2? and how do I do that?
Dynamic resistance of PN junction diode
diodes
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Best Answer
My take on this question:
Assume that: $$R >> r_{ac}$$ This is a reasonable assumption if E >> the threshold voltage of the diode.
V2 = only the AC component of the voltage measurement
$$r_{ac} = \frac{v_{ac}}{i_{ac}} = \frac{V_2}{\frac{V_1}{R_x + r_{ac}}}$$
$$r_{ac} = V_2.\frac{(R_x + r_{ac})}{V_1}$$
$$r_{ac}.V_1 = V_2.(r_{ac} + R_x)$$
$$r_{ac}.V_1 = r_{ac}.V_2 + R_x.V_2$$
$$r_{ac} = \frac{V_2.R_x}{(V_1 - V_2)}$$