I am using TPS61021 boost converter IC to increase input voltage from 1.2V to 3.3V. I have designed the boost converter from the application called TI WEBENCH.
Input Voltage: 1.2V
Output Voltage: 3.3V
Min current: 300mA
The PCB that I have designed, is measuring 3.3V, but the efficiency is pathetic. It is well below 25%. In the BOM, TI WEBENCH software recommends using 10UF 10V capacitor, but I am using 10uF 6.3V. I am not able to understand why efficiency is so low? Datasheet for Inductor.
Below in the tabular format I have written current values that I have measured from multimeter.
Fig.1 Measurement of current at different load resistance.
Best Answer
Pin = 1.2V × 570mA = 684 mW
Pout = 3.3V × 105 mA = 346.5 mW
Efficiency = Pout/Pin = 346.5/684 = 50.7%
How on Earth did you come up with 18.42%?
Similarly, I get 64% and 70% for your other two loads. These numbers actually sound pretty good to me at these voltages. Did Webench give you any efficiency estimates for this specific configuration?