Electrical – Calculating the voltage drop in AC circuit

acimpedance

I'm supposed to calculate the voltage drop (Ux). Where R=R=R=1kΩ, C=1µF, I=1mA, E= 2sin(ωt+pi/2), ω = 10^3 rad/s.

I know I have to use superposition method, but I dont know how to calculate impedance in both situations.

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Best Answer

  • 1 Substitute current source with it's output impedance. Ideally it is infinite, so leave it open.
  • 2 Calculate currents and voltages due to voltage source.
  • 3 Substitute voltage source with it's output impedance, Ideally, zero, so replace it with a short circuit to ground.
  • 4 Calculate currents and voltages due to current source. (Hint: it is DC, so what does that mean for the capacitor?)
  • 5 Add Corresponding currents and voltages from step 2 and 4.

Where is the top resistor connected to? It seems to float. If it is not connected at the other side, it has no function in this diagram.

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