Electrical – Class AB amplifier conduction angle

amplifier

This is a beginner's theoretical question. I was looking at the figures on this site: http://www.electronics-tutorials.ws/amplifier/amp_6.html and noticed that the so called "conducting angle" of a class AB amplifier is given this way:

enter image description here

It is said to conduct between 180° and 360°. What I don't understand is that the output signal is coming from two transistors, additive. I see that a single trasistor in the pair does not conduct in the full 360° range. But the amplifier as a whole does conduct at any angle right? The transfer function of the amplifier won't be a straight line (obviously), but I don't see where the signal is clipped. Please help me understand.

UPDATE: here is a graph showing two functions:

f(x) = min(-0.6, sin(x))
g(x) = max(0.6, sin(x))

I believe that the response of the whole amp to a sinusoidal input is something like f(x)+g(x)

enter image description here

Best Answer

Judging from the single diagram you post, run away from those web pages.

It seems they've managed to make a simple concept difficult to understand, and got it wrong in the process. What it appears that diagram is trying to show is how one of the transistors operates. However, what they are showing is class B operation, not class AB.

In class B, each transistor only conducts for exactly half the cycle, as shown. In class AB, there is a little crossover between the two transistors. Exactly in the middle, they are both conducting some. In the diagram you show, point Q should really be moved to the left a little, and the "output signal" biased up a little.

Added

Yes, your new diagram now shows true class AB behavior.