Electrical – direction of a dc motor with the help of 2 5 pin relays

Initial condition: no relays energized. One set of RY2's direct power one direction to the motor. Second condition: SW2 triggered, its NO contact energizes RY2, which reverses motor polarity and latches itself (you'll need a pair of diodes or another relay contact set to accomplish both reversal and latching). Third condition: SW2 released, RY2 is still latched, mechanism swings the opposite direction. Fourth condition: SW1 triggered, its NO contact energizes RY1. An NC contact set on RY1 breaks RY2's latching circuit, and the same NO contact latches RY1 on until power drops away. The second RY1 contact set's NC interrupts power to the motor.

EDIT: Here's what I have in mind:

Something like this should work. Note that the limit switches are different- one is normally closed and the other is normally open. If you have a relay with three form C contacts you can avoid using the diodes.

^{simulate this circuit – Schematic created using CircuitLab}

The two contacts are used to reverse the motor in the usual way, but one contact does double duty as a self-hold for the relay. The diodes prevent SW2 from shorting out the supply when the relay is de-energized and the limit switch to engage the relay is activated.

You can put a bridge rectifier across the motor to absorb inductive spikes from the motor inductance.