Electrical – How to wire a 5V 6-pin relay switching 110V AC @ ~35 W

raspberry pirelayswitcheswiring

Update:
Thanks for the help — working circuit below!

I am trying to turn on a 110V AC array of LEDs with a small 5V relay with some explosive results!! 🙂

I am not doing something right as I have successfully blown-up two of my relays…

Relay: HK4100F-DC5V-SHG

Spec Sheet: https://img.ozdisan.com/ETicaret_Dosya/445413_4369639.pdf

The Relay

There are 6 pins, the middle two pins are the coil. When I apply 5V DC I can hear it clicking which I think is expected operation.

I attach the load (array of LEDs) on the left of the photo.

I attach 110V AC from a wall socket on the right side.

Case 1:

  • a) No voltage to Coil.
  • b) Load and Power Source attached
  • c) Result is the LEDs are quite dim.
  • When I applied DC to coil the LEDs went out.

I'm not exactly sure why my relays exploded on subsequent attempts. Could it be that I reversed wires on the load, or power source? Should this even make a difference with AC?

Hoping this makes sense!

relay pinout from datasheet

Update:
Working circuit below:
enter image description here

Best Answer

As I read the datasheet, the two terminals on the left are connected together, and aare the common terminal (moving contact) of a single-pole, double throw switch. The top right is the Normally Open (NO) contact - with the relay not energized, it is not connected to anything. The bottom right terminal is the Normally Closed (NC) contact. With the relay not energized it is connected to the two left terminals.

When you energize the relay, the top right terminal will be connected to the two left terminals, and the bottom right terminal will have no connection.

Given that description, your drawing doesn't make sense - you seem to be applying 110 VAC between the NO and NC terminals.