I am trying to understand how a iv graph for a battery rated at 10V with internal resistance of 10 Ohms would look like. I was thinking it would just be a constant 10V for the graph, however, I am unsure how internal the internal resistance would impact the terminal voltage.

# Electrical – iv characteristic graph confusion

batteriesgraph

## Best Answer

^{simulate this circuit – Schematic created using CircuitLab}Figure 1. The 10 V battery can be modelled as an ideal 10 V source with a 10 Ω series resistance.Now you should be able to fill in the rest of the points. Calculate the voltage drop across R1 at 0.2, 0.4, 0.6 and 0.8 A and plot the resulting terminal voltage on the chart.