Electrical – MT3608 DC-DC converters in parallel with common output
circuit-designdc/dc converter
I'm thinking to use two DC-DC MT3608 converters in parallel with a single potentiometer.
Has anyone experience with these converters?, Any advice?.
Thanks
Best Answer
Has anyone experience with these converters?, Any advice?
The MT3608 that naturally produces a few milli volts (or several tens of mV) greater output voltage compared to the other one will win the "diode battle" and supply circa 90% of the load current.
But it gets a little worse. The diode supplying most of the load current will warm up more than the other and its forward voltage will drop hence, the "circa 90%" figure might become circa 95%: -
The most 'upper' buck-converter in the series connection will see the full input voltage as semiconductor blocking voltage in operation which will probably blow it up (84V input, specified for 36V).
Are there any concerns with this method, or better yet, is there a
better way to achieve this output?
Any kind of DC DC converter need a way to stabilize it's voltage and has a feedback loop, usually a voltage feedback loop. The loop needs to be stable to prevent oscillations (ripple) and also to prevent the voltage from dropping out. The loop also needs to be able to appear as a low impedance source. Not all converters (and their components ) can work across all voltage ranges. I only understand the basics, and can use tools to help me stabilize the loops (multiple semesters of courses can be dedicated to power control and switchers)
One method I am currently about to test is the LT8390, which markets itself as an adjustable DC DC conveter. The range also checks out in the tool, and you can use a current DAC to adjust the feedback loop.
Best Answer
The MT3608 that naturally produces a few milli volts (or several tens of mV) greater output voltage compared to the other one will win the "diode battle" and supply circa 90% of the load current.
But it gets a little worse. The diode supplying most of the load current will warm up more than the other and its forward voltage will drop hence, the "circa 90%" figure might become circa 95%: -
Picture from here.
Is this what you want?
By the way, you drew you circuit incorrectly. It should be like this: -