****WARNING: The tube drivers decsribed below make a very higher voltage to operate the tube. Hundreds of volts is typical. Over 1000V occurs on large CCFL units.
You can get a serious electric shock from these.**
- **If you do not take enough care you MAY die.****
I assume that you mean CCFLs "Cold Cathode Fluorescent Lights".
Like these -
IF they ran from the 12V from a SATA power plug you can run then from 12V. If so they will have had a controller which must be used with them. The controller converts the 12V to a higher voltage.
They may have run from the STA 5V supply - less likely. You need to connect to a SATA power supply socket and measure which voltages appear where ON THE INPUT TO THE CONTROLLER FROM THE SATA SOCKET. Do NOT try and measure the output voltages from the controller. Cheaper meters may emit magic smoke and meter users in some cases may emit magic smoke as well.
Useful CCFL page
CCFL driver IC datasheet - UCC3973 etc - shows what's involved. You do NOT want to build one of there. Commercial units are cheapish.
If they use ordinary small "incandescent" filament bulbs you will be able to run them on DC just as well. For practical purposes AC and DC of equal RMS value will work the same.
IF you can access the bulbs you will be able to replace them in due course with LEDs of similar appearance and brightness - but probably not something you want to try unless essential.
The operating specifications are somewhat contradictory.
2.5, 3.5 or 6V is a VAST range, suggesting they may be 6V bulbs that will run on lower voltages if needed, but at lower brightness.
110VAC/35 lights is about 3 V/bulb. 110 VAC/50 ~= 2.2 V/bulb
6V, 1.2 Watts is at the high end of what you'd expect.
It sounds like these are nominally 6V bulbs.
But operation on 6VDC to start is not recommended.
SO
Starting with a single alkaline cell (1.5V nominal) would tell you something.
I'd expect a dim orange glimmer.
Then try to a alkalines in series. That's 3V nominal. Doing this with no series resistor is extremely unlikely to do any damage. Being very old there is a very small chance that it might but it's very unlikely. I'd expect an OK appearance - maybe not as bright as on some strings. From what you get you can decide what to do next.
Above 3V I'd start with a series resistor.
Start with a 22 ohm resistor and if not bright enough try 6V and 22 ohms.
If 4.5V 22 ohms is bright enough then something like 6V with 33 ohms may be similar.
Once you have a 6V pack looking OK you can adjust the resistor up or down to suit brightness. Er on the side of too dim if you want them to last.
I've suggested going to 6V as battery voltage will vary with time and using 6V and a resistor will keep the brightness more constant over the battery life.
For a high tech [tm] solution that helps protect the filaments a constant current driver may be used. Ask if of interest.
Resistors mentioned above can be half Watt or more. 1 Watt safer but probably not needed..
Constant current supply:
Am LM317 IC can be used to provide a simply built constant current feed.
A "problem" is that the circuit "uses up" a minimum of about 3Volt to operate. So, if you run it from 6V you can only get 3V out. Whether this is a problem depends on Vbulb when it is a bright as you want it. Ideally you'll want even more than 4 batteries :-(.
Here R1 is shown adjustable but you can use set resistors which are changed to suit. Maximum likely bulb power was given by 6V, 1.2 W = 200 mA lamp current (0.2 x 6V = 1.2W. )
Current source current = Vref/R or
Resistor = Vref/Icurrent_source.
Here V = 1.2V regulator Cref, I = 0.2A max.
So R = V/I = 1.2V/0.2A = 6 ohms.
So if you make R1 >= 6 ohms at all times, then Ilamp <= 200 mA.
Add extra resistance to R1 to get lower lamp current.
Connect B+ to Vin.
Iout to bulb top
Bulb bottom connects to battery -.
Best Answer
That's a CCFL tube and the blue box is the power supply (inverter, driver) for it.