I looked on instructables and I found an interesting(at least for me) AM transmitter made with a 555 timer which acts as the oscillator:http://www.instructables.com/id/555-AM-Transmitter/ Is this idea feasible?Will it work?
Electronic – 555 AM transmitter
555amschematicstransmitter
Related Solutions
From what I can see form the circuit, the timer is running in astable mode. The frequency is controlled by the equivalent resistor made by adding resistances of P1 and R3, resistor R1 and capacitor C1.
If you want to experiment, go to 555 calculator and take a look at bottom schematic. Your P1+R3 are its R1, your R1 is its R2 and your C1 is its C.
UPDATE: I'll try to make it a bit clearer how this transmitter gets its frequency. First, read through the whole instructable. There is a nice explanation related to harmonics in it.
This transmitter controls antenna output using the Q1 transistor. The transistor is triggered by the output of the 555 timer. Therefore there is direct relation between 555 frequency and transmission frequency.
The timer itself is controlled by two resistors and a capacitor. Timer monitors situation on the C1 capacitor. When it is \$\frac {2}{3}\$ full, timer will emit high output and start discharging the capacitor. When it is \$\frac {1}{3}\$ full, timer will start emitting low output and start charging the capacitor. When the capacitor is charging, current is going through resistors (P1+R3) and R1. They limit the charging current and modify the time it takes to charge the capacitor. When the capacitor is being discharged, current goes from C1 through resistor R1 into discharge pin which is connected to ground during discharge. This way, R1 controls the discharge time.
Now about the 1.8 MHz band. You may be able to directly transmit at that band by using proper timer settings. For example TS555 timers made by STmicroelectroncs can provide up to 2.7 MHz frequency in astable mode. To get the 1.8 MHz frequency, you can use formulas from the 555 timer. Basically, you should pick the resistors, potentiometer and capacitor so that \$((R3+P1)+R1)*C1=8.05*10^{-7}\$. If you for example take a 22 pF capacitor (they are commonly used for microcontroller crystals oscillators), resistors added together should be around 37 \$k\Omega\$. You can take for example R1 to be 8.2 \$k\Omega\$ and then set the P1+R3 to be 20 \$k\Omega\$. After that, you can calculate exactly what kind of potentiometer and resistor you need for the transmitter to work correctly using the calculator.
I recommend that you do some more research before making the circuit with the values I recommended. Capacitors usually have high tolerances, so its impact on the circuit should be minimized. Resistors with 1% can be very cheaply obtained, but precise potentiometers or rheostats may be expensive. For example at local stores here, a good multi-turn potentiometer costs between 10€ and 20€, while cheap single turn one costs about 2€.
The point of the above paragraph is that there may be other set of values which could make it much easier and cheaper to set the correct frequency and provide higher precision. I unfortunately don't have enough experience to provide a better set of values.
It's probably worth going back to basics to answer this as there seem to be a few things muddle in the question.
A modulation is a means of altering a carrier so that it can carry information. A carrier can itself carry no information as it is periodic. FM is one scheme where the frequency of the carrier is changed slightly with each bit being emitted.
FM broadcast radio is an application of the frequency modulation of an audio signal to impress it upon a sinusoidal carrier, typically at 88-108MHz which is then broadcast as an RF wave.
There are other applications of frequency modulation and the 555 example you give is very much a different one. First of all, a 555 will almost certainly conk out at about 100kHz-1MHz, at very best no more than a few percent of the frequency you need.
Secondly, the values of the accompanying components would be so ridiculously small that they would be dominated by parasitics from your layout, pins etc, and very much not available in the shops.
Thirdly, the signal generated is square, not sinusoidal, so would almost certainly have truly epic harmonics at odd multiples of the carrier frequency such that in the very unlikely event that you got enough power to transmit any distance in the broadcast band, you'd soon be hearing a standard-issue boot at your front door when the relevant regulator arrived for the various shipping accidents and military incidents which your interference had caused. I'm gonna stop at three, but there are loads of other reasons.
Inductors are oddly frustrating to source order, my heart goes out to you on that, but if you want to work in RF you're going to have to get used to them, and also maybe choose a more conventional route in, ideally a legal one such as amateur radio or pre-assembled licensed/license-exempt modules?
Best Answer
No, it's rubbish: -
Look at the circuit - where do you connect a modulating input (such as a microphone or signal generator) - if you attached its output to an antenna it would be creating so many harmonics the whole of the AM broadcast band would be corrupted in the near vicinity.
Accepting that it's likely illegal to connect an antenna to the circuit there are far more practical circuits around like this: -
Taken from here. Or, there is this FM (not AM) one: -
Taken from here. Just Google "Simple AM transmitter" and look at the images of circuits you get. Choose one that is within your capabilities and go to the source page for instructions and help.