Electronic – Accidentally downmixed stereo to mono, why does this work

audiomixerspeakersstereosumming

I have a cheap Chinese Bluetooth audio amplifier like this:

enter image description here

It has four screw terminals for the speaker connections, namely L+, L-, R+ and R-. I accidentally connected a single speaker to L+ and R-, and was surprised to find that I could hear both the left and right channel over the single speaker. I decided to experiment and found out that if you connect the speaker the proper way (so either to L- and L+, or to R- and R+) it would only play the single channel you'd expect it to play, but if you connected either L+ and R- or R+ and L-, it would "downmix" both stereo channels to a single channel and play them both over the single speaker.

I've been trying to wrap my head around how that works, but I can't figure it out. Is the board more sophisticated than I expected and does it output mono when it discovers no load on the different terminals, or is there something else going on?

Best Answer

This can be easier to understand if you look at the waveforms.

In a push-pull, or bridge amplifier both lines are driven as shown below. enter image description here enter image description here

Notice \$L-\$ is literally the inverse of \$L+\$

Similarly the other signal, \$R-\$ is the inverse of \$R+\$

The difference between the +/- voltages is that excites the speakers.

Now, if you connect Opposites to one speaker the difference in signal becomes the mixture of both signals. Hey-Presto.. you have a mono system.

Note however, the amplitude of each "Side" is now effectively reduced by half. If you can't understand that, consider the case where there is no signal on the \$R\$ side. The difference between the blue lines is now only half what is was between \$L+\$ and \$L-\$.

If the original sound was recorded central, that is, an equal waveform on both left and right channels, the \$L+\$ waveform would be identical to the \$R+\$ waveform, same for the negatives. As such, joining \$L+\$ with \$R+\$ would result in no voltage difference for that sound. That is why you need to cross connect them.