Electronic – Biasing of a circuit with two transistors BJT

biasbiasingbjttransistors

I need to calculate the bias values. So far I have only written these equations, but something is missing. (\$\beta=200\$ for both transistors and \$V_{BE\,on}=0,6\,V\$)
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Capacitors=open circuits

\$\frac{20-V_{C1}}{R_2}=\frac{V_{C1}-0,6}{R_1}+I_{B2}\$

\$I_{E2}=I_{C2}\times \frac{\beta+1}{\beta}\$

What equations are missing me?

Best Answer

\$V_{CE1} = I_{B1}\cdot R1 + V_{BE}\$ (1)

Collector-emitter of Q1 is parallel to base-emitter of Q2 plus R3. So,

\$V_{CE1} = I_{C2}\cdot R3 + V_{BE}\$ (2)

From (1) = (2), \$I_{B1} \cdot 1000k = I_{C2} \cdot 3.3k\$.

I'm sure you can take it from there by yourself.