Electronic – Charged capacitor doesn’t allow impulses to pass

capacitor

I tried this circuit and was confused about the theory of capacitors.

Here's what I'm supposed to do: on pressing S1, the capacitor is charged and the led blinks for a second. On pressing S2, the capacitor discharges.

When I try to press S1 without discharging the capacitor again, the led doesn't blink. Now capacitors are supposed to allow change in voltages across them i.e. the led should blink when the capacitor is charged, right? Why doesn't it?

Circuit diagram

Best Answer

Initially, the voltage on the + plate of the capacitor is 0V.

Pressing S1 connects it to a 9V source; current flows, charging the capacitor.

On releasing S1, the voltage on the + plate of the capacitor remains at 9V.

Pressing S1 again connects a 9V source to a plate charged to a potential of 9V, so no current flows. The LED does not light again.

If you attach a highish value resistor (10k-100k) between the + plate and ground, it will discharge the capacitor between presses of S1, so it will light again for each press of S1.