Voltage Measurement – Determine Voltage Drop Over 10G Resistors with Cheap Multimeter

multimetervoltage measurement

I have two 10G resistors connected in series with a 3V battery. I want to determine the voltage drop across one of them, which of course is 1.5V. When I use my multimeter to check the voltage drop, it reads ~3mV, which I believe is because it has a 10M impedance so the circuit is really one 10G resistor in series with (a 10G resistor and a 10M resistor in parallel), so the voltage drop when the multimeter is part of the circuit is 2.99 mV.

schematic

simulate this circuit – Schematic created using CircuitLab

How can I measure the voltage drop? Is there something I can build so that that I can adapt the multimeter impedance to be high enough that it won't affect the circuit as much?

Best Answer

Do what the ancients did ==== use a Wheatstone bridge. Like this

schematic

simulate this circuit – Schematic created using CircuitLab

Rotate the 10,000 ohm potentiometer for ZERO reading.

Then measure the pot voltage (and compensate for the DVM loading)