Electronic – Help with NPN and PNP common emitter


I have a circuit that has the emitter side of a NPN tied to the emitter side of PNP. I need to find the output voltage on the emitter. Base voltage is a sine wave. Can someone help me understand what this kind of configuration is used for? And how should I go about to calculate the power dissipated by the resistor?

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Best Answer

You mean like this?

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This is a push-pull emitter follower. The ideal case: the output equals the input. The practical case: there is a Vbe (~0.7V) crossover distortion which causes a deadband for input signals around 0V.