I have an analog signal which ranges between 0V and 10V. I want to linearly scale it down to 0 to 2.5V for my ADC.
I'm concerned that using a resistive voltage divider will affect signal quality. Is this true? If it's not true, what value resistor should I use for voltage divider?
Best Answer
Yes, a voltage divider is fine in theory. How much it effects signal quality is in large part dependent on what you consider a quality signal. Is this HiFi audio, a digital data stream, voice audio, RF, something else?
There are several issues with resistive voltage dividers you should be aware of:
In this case R1 = 3*R2. The impedance looking into the divider from the source will be R1+R2. You have to make sure this is high enough to not load the source signal to change its characteristics to the point you care. For example, if R1=30kΩ and R2=10kΩ, then the divider will load the source with 40kΩ.
One way to deal with this is to add deliberate capacitance as small as possible but several times the expected stray capacitance so that the total capacitance becomes predictable. The capacitance accross each resistor must be inversely proportional to that resistance. For example, here is a nicely ballanced voltage divider:
At low frequencies, the resistors dominate and divide the signal by 4. At high frequencies, the capacitors dominate and divide the signal by 4. The crossover where the resistive and capacitive actions are about equal is 53 kHz in this example.
By the way, this is how dividing scope probes work. A "10x" probe divides the signal by 10. Since it needs to do that accross the scope's whole frequency range, a little capacitance is added to each resistor. The stray capacitance can never be exactly known and there will be some part tolerance anyway, so one of the capacitors is made variable. This is what the "probe compensation" adjustment is. This adjustment turns a small trim cap of a few pF. With a square wave in, you can see easily see the point where the capacitive and resistive dividers match.
One drawback of this capacitive and resistive approach is that the impedance of the divider goes down at high frequencies. While this approach is useful for properly dividing higher frequencies, it also loads them much more than just two resistors would. There is no free lunch.
Hopefully you can see some of the issues and tradeoffs now. If the impedances don't work out, then you need to consider some kind of active buffering like Steven already described. That has it's own set of issues, like offset voltage, frequency response, and gain error if gain is not just 1, but those are for another thread.