Here is what I know about the Ideal Op-Amp.
- The open loop voltage gain is infinite
- The output voltage is given by the following \$v_o = A(v_+ – v_-)\$
- Only with a negative feedback loop is \$ v_+ = v_-\$
My queries are as follows:
- Clearly, \$v_o = A(v_+ – v_-)\$ should still apply and since \$ v_+ = v_-\$, shouldn't the output voltage \$ v_o = 0 \$ always?
- Since \$v_o = A(v_+ – v_-)\$ should still apply, is A still the open-loop voltage gain which for an ideal op-amp is infinity. Thus, would the output voltage always be infinity?