Electronic – Lead Acid AGM battery testing – Why am I testing it this way

acidbatterieschargingleadtesting

OK, so maybe it's not fair asking YOU why WE test something the way we do. 😉

Here's the thing — Our company uses AGM Lead acid batteries in some products. The testing methods are ancient (but so is lead-acid technology). There's nobody left in the company to ask these questions of. We have "what" well documented, but rarely is "why" written down.

Our application is most similar to a golf cart or fork lift. "Traction batteries" I believe these would be called.

I've asked the battery manufacturers but I can't get a straight answer. I suspect this may be a case of Llama Dung

For a 12V battery (example) we do 150 cycles of the following:

  • Discharge battery at 13A until voltage reaches 8V
  • Rest 3 minutes (during this time, the battery voltage will recover)
  • Discharge at 5A until voltage reaches 10V
  • Perform slow charge (about 8 hours) until battery is fully charged
  • Repeat ad nauseum

The part nobody can explain is why we do a 2nd, lower current drain of the battery before recharging.

This may be a chemistry question (in which case I'm not qualified to really understand the answer I'm sure).

Anybody know something about this that I've failed to be able to Google?? (Believe me, I tried!!!)

Heck I even read the relevant sections of Lindens "Handbook of Batteries". All I could find was this one sentence..

" Intermittent discharge, which allows time for the electrolyte to recirculate, or forced circulation of the electrolyte will improve high-rate performance. "

Best Answer

You could do the entire discharge at the lower rate but then it would take a lot more time.

When discharging at a high rate the voltage may collapse prematurely so the battery seems discharged before it really is.

By combining the two discharge rates you can discharge the battery in a reasonable time but be confident that it is fully discharged.

The lead-acid chemistry is somewhat unusual among rechargeable batteries in that the electrolyte is consumed in the discharge process. Being converted to water with the sulfate ions combining with the lead plate to form lead sulfate.

As a result at high rates of discharge, the electrolyte within the plates becomes progressively more dilute, the discharge for that portion of the plate slows down and the cell voltage drops. At lower rates of discharge, fresh electrolyte can diffuse into the plate fast enough to support the chemical reactions and the discharge can continue further. This is the meaning of the last sentence of your question.

Peukerts's Law