on my design, I am using two coin batteries in parallel and each battery has a Schottky diode in series to block the reverse current, in theory, it will avoid the higher potential battery "charge" the lower potential battery.
But I am facing a higher current consumption when the two batteries are connected to the circuit, probably in reverse leak
Single Battery connected avg consumption 2.6uA
Two Batteries Connected Average Consumption 7.8uA
What should be the recommended to avoid that probable reverse current leak?
Change diodes, add a second diode in series (2 diodes per battery), replace diodes per an ideal diode IC?
update
diodes:MBR0520L
The voltage at uC e.g: 3V it takes higher voltage between the two Batteries, usually exist few 1-15mV in the difference between each battery
Best Answer
The reverse leakage current is not drawn into the datasheet diagrams for such low reverse voltages, but extrapolating the curve does indicate near 5uA of current could flow. For example a BAS40 would have 3 nanoamperes of reverse current at matching conditions so changing the schottky diode to a better might help.