I was reading about full-wave rectifiers and came across the schematics below which the capacitor C can smooth its voltage, but I didn't understand one case:
We know that when the rectifier's voltage begins to falling from its peak, the cap C starts to send its charge to load. Where does the falling current coming from FW rectifiers go? (The current from peak to zero and that one who rises from zero to the point which the cap starts to charge in diagram) Is it blocked, by diode or capacitor? Why?