Electronic – TPS63050 Enable Pin Pull-down Resistor

integrated-circuitpulldownresistors

I'm using the TPS63050 buck/boost converter in a design. The datasheet basically just says "don't leave it floating" in the table on page 4. I want this enable pin to be under the control of an external circuit, and so I will implement a pull-down resistor on that pin to accommodate the condition where that external circuit would otherwise float the pin. What I can't quite ascertain from the datasheet is, how big a resistor can I get away with for this purpose. I was thinking of populating a 1 MegaOhm resistor to GND, to minimize the static current draw required just to enable the regulator.

Is there any reason I should be concerned, or any likely problem, with using such a large resistance in this context? My gut says it should be fine, but it would make me feel even better to get some positive affirmation or advice to the contrary from my colleagues here on EESE!

Best Answer

Since the leakage on that pin is so low (high impedance), you risk the pin being susceptible to interference with such a high value resistor. Something more reasonable like 10 kΩ would probably be better, but still not needed.

This pin is usually just shorted to the power rail. The static current draw will be next to nothing (typically 0.01 µA).