Electronic – Why does this connection not become a low impedance between Positive (Isolated system) and Ground (Earth)

earthgroundinggroundloopsoscilloscopevoltage

I was going through a lecture regarding oscilloscope grounding methods and saw this image.

Assume I have the isolated widget powered by an external battery. Now, I am going to measure the signals using an oscilloscope.

Question : Why does the current not flow between the "Power In" rail in my widget and the "Mains earth ground" when I connect my oscilloscope alligator clip ground to the "Power In" Rail of the widget – as shown in red in my above image?

I believe that the Current follows through the path of least resistance. When the scope ground (which is connected to the earth's main) is connected to the +V in my widget, does the +V not have a least resistance path to ground (Earth in this case – assuming earth is lower potential that +V rail)?

I am having this confusion and not able to understand clearly why the current does not flow. Can someone please explain in simple terms on how to understand this?

I understand the when I connect the scope ground to any point on my widget, that point will be "Earth" referenced. But, I am not getting how the current does not flow between the +V and Earth when the above connection is made?

P.S. the lectures says that since the widget is isolated and has its own +V and negative, "there are no loops formed when the oscilloscope ground is connected to the +V and that's why current does not flow from the +V to the scope ground" – I am still not getting this. Any analogy or illustrations with simple terms explanation will greatly help me understand.

Best Answer

its because the V+ in the battery powered circuit is only positive relative to the battery GND. To the rest of the world it's floating/undefined until you connect the oscilloscope gnd. Now V+ of the Battery battery powered circuit is equal to the oscilloscope gnd. Still no current flows. you just have defined voltage potentials now. The Battery battery powered circuit gnd is not equal to oscilloscope gnd but negative (oscilloscope gnd minus V+). So if you now measure at the Battery battery powered circuit voltages will be shown as negative values

So first have a look to the oscilloscope - its galvanic isolated (but neutral and secondary side GND might be coupled). If GND is floating, wherever you connect it, it is tied to the potentials of the device under test.

second is your example in 3 steps starting with no connection to full connection with GND and probe:

example