Electronic – Wiring LED Lights Together and Running off of 3V Power Supply

led

I've looked around this forum but not found the answers I'm looking for. I've found some similar questions being asked, but this project is a bit specific so the answers were not really applicable to my situation. Also, I am very much a novice at this kind of thing. Maybe some of you experts will be able to help. Here's the background then…

I've got four decorative letters (one is actually a heart) which hang on the wall and are lit with white LEDs. Two have 10 LEDs, one has 11 and the other 12, so 43 white LEDs in total. Each 3V unit is powered by two 1.5V AAA batteries and each has its own on/off switch built into the battery compartment.

However, it's a real faff having to remove each unit separately from the wall twice a night, to switch them on and later to turn them off. The batteries don't last that long either and I seem to be constantly changing them.

So, in a moment of true innovation (for me anyway), I decided to mount them all permanently on a board that's painted the same colour as the wall and to wire the four 3V units in parallel to a 3V 1A mains power supply.

To complicate things slightly, I've also got four switches which are actually 12V car accessories (to switch on/off each of the units) and each switch also has a colored led in the rocker (1 x red, 1 x green, 1 x blue and 1 x yellow). I've tried connecting one switch to 2 x AA batteries as a test and the LED seemed to light up fine.

My questions are then, does this power supply sound like it would work okay with my LEDs and if so, how should I wire the units up? I'm guessing each 3V unit should be wired to the power supply in parallel. But if that is the case, should I also put some kind of resistor in the circuit for each unit and if so, what value?

Sorry, I'm a bit of a novice at stuff like this so thank you in advance for any advice you can give.

Best Answer

Each letter most likely consists of a number of LEDs wired in parallel to the voltage source; itself two 1.5V cells in series for 3V total. Ideally, each LED will have its own current-limiting resistor, but sometimes they are omitted to reduce costs (such as with coin-cell powered devices).

AAA cells (like any alkaline cell) have internal resistance. Per the Energizer datasheet, this is 150-300 mΩ. In theory this means a maximum current, albeit for a very short time, of \$\frac{1.5V}{0.15Ω} = 10A\$, far more than an LED can withstand. This suggests to me that the product should have current-limiting resistors somewhere inside. You might want to inspect and post a photo to be sure.

schematic

simulate this circuit – Schematic created using CircuitLab

If this is the case, replacing the batteries with a line-powered 3V source should work. You could take some measurements with a multimeter to determine this more reliably.

To connect the letters together, you're correct that they should be in parallel:

schematic

simulate this circuit

The switches you have are likely for 12V use, and probably already have a current-limiting resistor for the internal LED. If they are lighting at all with 3V you can simply connect the two LED terminals on the switch in parallel to the letter it controls:

schematic

simulate this circuit