Electronic – wrong with the KVL approach on a really simple circuit

circuit analysis

Circuit

Hello, so this is a really simple circuit question that has been bothering me. I know that by simply looking at the circuit and using logic it makes sense that the voltage drop across the resistor(as pointed in the picture) should be 0.6V. But when I actually write the Kirchoff Voltage Law(KVL) around the loop as shown in the picture, I somehow get -1.8V. I am probably messing up my convention. Would someone please explain how I would get the same 0.6V using KVL as well?

Edit: found the answer from my class notes for your refernce. Is the solution assuming opposite convention for how the current flows in the circuit so as opposed to positive to minus terminal is it assuming minus to positive?

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Best Answer

I think the direction of current given in the problem is backwards, or the polarity of the voltage source is upside down. That would make 0.6V the correct answer.

I say this because it is impossible to have 1.8V across a resistor in a circuit if the only source is 1.2V (regardless of polarity).

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