While I've never heard of this circuit before, I watched the video @user23711 linked. I think I can give you a decent explanation.
Essentially, you have an AC source driving your device with a resistor in series acting as a current limiter. The voltage measurement is simple. You are literally just measuring the voltage across the device under test, just like any other voltage measurement with an oscilloscope or multimeter.
As for current, you are measuring the voltage across the resistor and not the device under test (DUT) because voltage is (sort of) proportional to current in a resistor. Since the resistor is in series with the DUT, the current is the same as that of the DUT. However, the voltage across the resistor will be proportional to the current while the voltage of the DUT has an unknown relationship to current. That is, after all, the purpose of this circuit.
Now, if you had a current probe for your scope, you wouldn't need this test setup. Also, be mindful that the V/I curve for a resistor is not perfectly linear. If you are looking for high accuracy this might not be the way to go.
Finally, the reason for the AC source is to frequently enough cycle the voltage of the DUT. Then, when using XY mode on the scope, the IV curve of the DUT can be seen. But really, you could use any source you want (that won't break the DUT), and view the voltage and current curves with respect to time.
You're confusing "high voltage" with "high voltage loss". Ohm's Law governs the loss of voltage across a resistance for a given current passing through it. Since the current is low, the voltage loss is correspondingly low.
Best Answer
A fixed-resistor potential divider reduces an input voltage to a lower value at the output: -
If you imagine that \$R_{top}\$ and \$R_{bottom}\$ are combined into one resistor then the wiper position is where top and bottom resistors meet mathematically ; the resistance above the wiper (\$R_{top}\$) is exactly as it was with two separate resistors and the the resistance below the wiper (\$R_{bottom}\$ is also the same.
So, with a potentiometer you vary the tap-point and this means your output voltage can be varied between 0V and Vin.