I have a circuit of two capacitors and three resitors, where two pairs of the components are in parallel combinations:
I'm trying to calculate the total impedance.
Since \$C_1\$ and \$R_1\$ are in parallel and likewise \$C_2\$ and \$R_2\$ i would think the solution would be:
\$Z_E = R_1 + \frac{1}{j\omega C_1} + R_2 + \frac{1}{j\omega C_2} + R_3\$
However my textbook tells me that the answer is what's given on the picture.
Can anyone clarify this for me? Thank you.
Best Answer
Let's translate your words into an equation for the equivalent impedance.
$$Z_1 = R_1||\frac{1}{sC_1}$$
$$Z_2 = R_2||\frac{1}{sC_2}$$
$$Z_E = Z_1 + Z_2 + R_3$$