We know that current transformer is used to step down the current of the primary side. So basically it is a STEP UP transformer. Also we say that current transformer basically works on close to short circuit mode.
So if \$ {V1\over V2} = {I2\over I1} = {N1\over N2} \$ and N2 >> N1 so V2 should be also very much high than V1. So if we are trying to short circuit this large voltage, how it is going to work as large current will flow in the secondary also. Don't you think it is going fundamentally wrong?
Best Answer
There's no contradiction. When you limit the secondary voltage by putting a load across it, the primary voltage becomes proportionally lower, too.
You can think of it as having the secondary load resistance "appearing" in parallel with the primary, but with a value that's reduced by a factor of \$(\frac{N_2}{N_1})^2\$. When you put a given current through this combined impedance, the voltage drop across the primary is much lower than it otherwise would be.