I have designed a circuit for water pump. Please correct me if I am wrong with schematics. The idea is to to switch on/off AC motor pump with 230V and 7.5A, when water is detected.
I have used opto-isolator MOC3063M and triac BT137.
I have four questions:
Thanks.
P.S. Water detector is nothing but plate with two conductors to detect water presence.
Additional: Yes you are right 1.5V is too small, because of voltage drops of led D1 and the led in MOC3063. I consider to use 6V DC power source.
Best Answer
As others have noted in the comments, the voltage is not high enough. Assuming the WD1 output is a relay, you might be able to get rid of the indicator LED and use that circuit, perhaps with an indicator light across the pump motor. Alternately, use a 5V wall wart supply and increase R1 to get the proper current.
The triac drive circuit looks okay, suggest a higher value for C1, maybe 0.1uF with appropriate AC voltage rating.
Fuse placement should be in the 'hot' line- it's not clear if that's what you have done.
Heating will be around 7-10W so you need a fat heatsink for the triac. Note that the 8A BT137 is grossly underrated for a 7.5A motor load and will probably fail 'on' at the first opportunity. Suggest using at least a 25A triac (40A would not be too excessive) and giving it a large heatsink.