Water pump with opto-isolator MOC3063M and triac BT137

opto-isolatortriac

I have designed a circuit for water pump. Please correct me if I am wrong with schematics. The idea is to to switch on/off AC motor pump with 230V and 7.5A, when water is detected.

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I have used opto-isolator MOC3063M and triac BT137.

I have four questions:

  • Can be used 1.5V to signal water detection or should be at least 6V? The current should be not more than 25mA.
  • Is it RC snubber set up correctly including resistors R2, R3?
  • Is it FUSE in right place? Should it places before RC snubber or after that
  • Can be used additional measure for heating? For example heatsink or another alternative.
  • Thanks.

    P.S. Water detector is nothing but plate with two conductors to detect water presence.

    Additional: Yes you are right 1.5V is too small, because of voltage drops of led D1 and the led in MOC3063. I consider to use 6V DC power source.

    Best Answer

    1. As others have noted in the comments, the voltage is not high enough. Assuming the WD1 output is a relay, you might be able to get rid of the indicator LED and use that circuit, perhaps with an indicator light across the pump motor. Alternately, use a 5V wall wart supply and increase R1 to get the proper current.

    2. The triac drive circuit looks okay, suggest a higher value for C1, maybe 0.1uF with appropriate AC voltage rating.

    3. Fuse placement should be in the 'hot' line- it's not clear if that's what you have done.

    4. Heating will be around 7-10W so you need a fat heatsink for the triac. Note that the 8A BT137 is grossly underrated for a 7.5A motor load and will probably fail 'on' at the first opportunity. Suggest using at least a 25A triac (40A would not be too excessive) and giving it a large heatsink.

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