Electrical – 3 Input XNOR gate made with XOR and not gates

boolean-algebradigital-logiclogic-gates

hi i have implemented this equation with XOR and Not gate but i'm not getting the correct answers
(A.B.C)+(A'.B'.C')

What is the Problem ?
thank you

Best Answer

What you should get is an XNOR gate (Y=A'B'C'+ABC'+A'BC+AB'C) "an even number of ones". As an XOR gate will give an output that is true if and only if an "odd number of ones" is deriving it. So, inverting the XOR gate will results in an XNOR gate that will give an output which is true if and only if an "even number of ones" is deriving it.

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Electronic – XOR Gate malfunctioning

The part you're looking at has open-collector outputs. Consequently, every place its output is specified as "high", what it really means is "floating". This allows the outputs from multiple xor gates to be 'and'ed by simply tying them all together and attaching a single pull-up resistor to the lot of them.

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Truth tables:

NOR (NOT-OR) is more or less like NAND:

0 NOR 0 = NOT(0 OR 0) = NOT(0) = 1
0 NOR 1 = NOT(0 OR 1) = NOT(1) = 0
1 NOR 0 = NOT(1 OR 0) = NOT(1) = 0
1 NOR 1 = NOT(1 OR 1) = NOT(1) = 0

XOR emits 1 when the two inputs differ. You can consider this as binary addition without carry.

A XOR B = (NOT(A) AND B) OR (A AND NOT(B))

0 XOR 0 = 0
0 XOR 1 = 1
1 XOR 0 = 1
1 XOR 1 = 0

Best Answer

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