When I tried to use Source Transformation method on the 12 V voltage source the problem gave me a wrong answer. If I transformed the 2 A current source it works just fine. My question here, Is there any Cases in Deducing Norton and Thevenin equivalents where I cannot use source transformation method?
The right answer for I Norton is -0.4 A
Best Answer
There is no Thevenin equivalent for an ideal current source.
There is no Norton equivalent for an ideal voltage source.
Any other linear one-port network (meaning a network of linear resistors, ideal voltage and current sources, and linear dependent sources) will have an I-V curve from which either a Thevenin or Norton equivalent circuit can be found.