I am a beginner in assembler language I was reading some stuff online(belongs to a university) and I saw that
the P bit in psw after executing this instruction mov a,#03h A=0000 0011B so P=0
first it was difficult to know what is p bit after some research I thought it is parity bit and then you have to count the number of one bits in the result so the number of 1 bit in the result is 2 so it is an even number so P must be equal to one so why is P equal to zero here ?
Electrical – Assembler language basics parity flag
assemblerbinaryflagmicrocontrollerparity
Best Answer
It's probably an even parity bit.
The count of all the bits that are ones PLUS the parity bit should be an even number.
Examples:
\$0 0 0 0 0 0 1 1\$ \$Parity = 0\$, \$\Sigma= 2 + 0 = 2\$
\$0 0 0 0 0 0 0 1\$ \$Parity = 1\$, \$\Sigma= 1 + 1 = 2\$
\$0 0 1 0 1 0 1 1\$ \$Parity = 0\$, \$\Sigma= 4 + 0 = 4\$
\$0 1 1 0 0 1 1 1\$ \$Parity = 1\$, \$\Sigma= 5 + 1 = 6\$