Electrical – Calculating Thevenin impedance

circuit analysisimpedancethevenin

This is the circuit I'm given:

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And after disabling all of the sources, I'm now trying to calculate the equivalent impedance (which would be the Thevenin impedance):

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But I'm stumped on how to combine the capacitor and the 2 kohm resistor. Seems like a dumb thing to ask but are they in series or parallel? I've debated myself on both counts. There's a trivial loop there so they are in parallel. But there's a trivial node connecting these two so they are in series? Am i just being dumb here and there's an obvious answer?

Best Answer

I think capacitor and resistor are in series but then they combined are in parallel with a piece of wire which has least resistance(impedance in AC) so i think total impedance would be 2k