Electrical – Circuit with two voltage dividers in parallel

circuit analysisoutputresistorsvoltage

I have the below circuit.
enter image description here

I'm solving for Vx. Vx is just Vout for another voltage divider. So, the top left R is R1 the bottom is R2. Therefore shouldn't Vx be R/3R (Vs) = 1/3 Vs?

But it's actually enter image description here

Best Answer


simulate this circuit – Schematic created using CircuitLab

This circuit proves intuitively that Vx = V1.(2/5)

Alternatively Millman's theorem can be used or just combining resistors in parallel and series in potential divider fashion also proves this.