Electrical – Closed-Loop Voltage Gain of Circuit Problem

gaininverting-amplifieroperational-amplifier

This might be a simple problem, but I simply cannot wrap my head around it; I'm still learning about ideal op-amps and electronics in general.

The problem is:

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I have tried solving it using the gain formula for an inverting op-amp configuration, which goes "Av = -(Rf/R1)".

I determined an equivalent resistance for the top 5 resistors (R||R + R||R + R = 2R) and divided that by the resistor at the inverted input, which that gave me an answer of -2, where it should be -8, according to my professor's solution.

What the hell am I doing wrong, help is greatly appreciated!

Best Answer

Write a KCL for each of the two nodes on the T-Network, namely \$V_a\$ and \$V_b\$.

Notice that we have:

\$\dfrac{V_{in}}{R}=-\dfrac{V_a}{R}\$

KCL for the two nodes:

\$\dfrac{2V_a}{R}\$ + \$\dfrac{V_a-V_b}{R}\$ = 0 ,

\$\dfrac{V_b}{R}\$ + \$\dfrac{V_b-V_a}{R}\$ + \$\dfrac{V_b-V_o}{R} \$ = 0

Thus,

\$\ 3V_a - V_b = 0 \$

\$\ 3V_b - V_a = V_o \$

Plug em into mathematica and you'll get:

\$\ V_a = \dfrac{V_o}{8}\$

And:

\$\dfrac{V_o}{V_{in}} = -8\$