Electrical – Does grounding to earth make a circuit (allowing electricity to flow)

currentearthgroundvoltage

This question is mostly extending on a question that has been asked here:
Single terminal of voltage source attached to earth ground

I'm learning the basics of electronics and this question has always bothered me. The post above explains that a single terminal of a voltage source, when connected to ground (earth), will have no current flowing, as there is no circuit. It then goes on to talk about how capacitance might play a small factor.

My main question is this: Why then would you get electrocuted if you touched a live wire while grounded, since it is not a proper circuit? Is it different with AC and DC?

Also, when the single terminal of a flyback transformer (usually the anode cap on a CRT monitor) is placed near the ground, it creates a bright arc to the ground. How does that happen if it's not a complete circuit? In high voltage projects, most people connect the live wire from the flyback transformer straight to ground to complete the circuit.

Best Answer

Why then would you get electrocuted if you touched a live wire while grounded, since it is not a proper circuit?

Because it IS a proper circuit.

If the return wire of the high voltage source is grounded then, touching the live wire will close a circuit where your body (also grounded as per the quote above) is the "load" and a current will flow.

If the high voltage source were floating i.e. it didn't make a connection to ground then you might feel a little tingle when first touching the live wire but this is due to discharging the small amount of capacitance that the floating voltage source has (with respect to ground).

Also, when the single terminal of a flyback transformer (usually the anode cap on a CRT monitor) is placed near the ground, it creates a bright arc to the ground. How does that happen if it's not a complete circuit?

Usually, the high voltage winding of a CRT flyback transformer is grounded (or partially grounded via a resistor) and therefore the arc is completing a circuit.