I am really confused why D1 (Dual Switching Diode) is used in the amplifier circuit. I used NEGATIVE impulse signal generator to trace signal at C6 and was almost 10x smaller (OpAmp ckt. was isolated) …..Is it impedance mismatched between signal generator and Diode Configuration itself?
Also, I let impedance of signal generator determine gain of an OpAmp (U3). So, usual Rg is missing. Then, I used dual power supply Vs = +/- 5V as suggested in datasheet. OpAmp BLEW UP twice. I verified circuit connection as well. No short circuit anywhere when circuit is power off. As soon as, power is ON the OpAmp gets hot, smokes and 🙁
I use linear voltage regulator to supply +9V (TPS71501) and -3 V (TPS72301) to power up an OpAmp and it works fine. Circuit exactly as data. Note that: TPS72301 has internal Thermal/Current protection.
But, when I try to use dual power supply the OpAmp gets very hot.
Why am I doing this???
I want to figure out accurate rail voltage so that when i use an impulse signal above -1.5V to -4V, I do not have signal clipping problem due to +/- Vs.
Any thoughts or suggestions!!! Much appreciated