Electrical – Equivalent Current in Circuit

circuit analysiscircuit-theorykirchhoffs-lawssuperposition

I have the following circuit:

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I'm trying to calculate the equivalent current. In my approach resistors 2 and 1 are in parallel so their equivalent resistance would be 2/3 then since resistors 1 and 2/3 are in series I will get an equivalent resistance of 5/3

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Now since the 2 resistances are in parallel I get the equivalent resistance as 1.06. Now the current in the circuit is \$V/R\$ so \$1/1.06=0.94\$. But the answer in the textbook says it's 0.66. Please let me know what I'm doing wrong here.

Best Answer

The left 1ohm resistor does not affect the circuit at all, you might as well remove it.

Then the remaining 1ohm and 2ohm resistors are in series making them effectively a single 3ohm resistor.

Then the two 3ohm resistors are in parallel, giving a single 1.5ohm resistor.

And finally 1V/1.5ohm is 0.67A.

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