I am now designing an FM demodulator circuit. And the first step is turning FM into AM, so I could use envelope detector afterwards. Modulator circuit is designed using Colpitts topology. So frequency varies from 2,336 MHz to 2,411 MHz (according to my calculations).
The resonance frequency of the following circuit with C5=10pF and L2=435uH is about 2,413MHz. So the amplitude of the output should change depending on the frequency of modulator circuit.
Unfortunately I can't "observe" it neither at my "voltage-time" plot nor at FFT. Maybe I am doing smth. wrong or some basic considerations are not proper. Thank you in advance!
FM Demodulator – FM Demodulator in LTspice
amdemodulationfftfmresonance
Best Answer
Looking at your demodulating slope detector, it has a Q of about 1.52 and, if I plug numbers into an on-line calculator, I estimate that at 2.331 MHz (slightly lower than 2.336 MHz), the amplitude drop is 0.047 dB compared to that when the frequency is 2.413 MHz.
In real numbers, you should expect to see an amplitude change of about 0.54%. Maybe that's what you see. Nevertheless, it's a pretty poor slope detector if that's all it brings to the party. I would use a high pass filter like this: -
Of course you could make the Q a bit bigger and get more conversion of frequency to amplitude. The operating frequency isn't that high to worry about matching loads so you have scope here.