Wheatstone bridge is used for temperature compensation for strain gauges
If 2 strain gauges are connected like this figure. Due to temperature variation; the resistance Rg will change in the same way.
Lets say; the bridge is balanced at start.
R1/R2 = (RG+DeltaR)/(RG-DeltaR)
If strain gauge resistance increases due to temperature:
R1/R2 = (RG+DeltaR+RT)/(RG-DeltaR+RT)
How does this compensation work?
(RG+DeltaR+RT)/(RG-DeltaR+RT) is not the same as (RG+DeltaR)/(RG-DeltaR)
So gets the bridge unbalanced???
Best Answer
A real 4 element strain gauge is designed to have compensation like this: -
As you should be able to see, the temperature compensation "modifies" the gain of "both paths" in the bridge because it is in series with the excitation voltage/current. That's how temperature compensation works on a real device whether it is full-bridge or half-bridged active elements.