Electrical – How exactly are the phase shift and cutoff frequency defined for a filter + amplifier circuit

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Say we had a voltage source connected to a Low Pass RC filter and that this filter was connected to the negative node of an Operational Amplifier, so we would have a filter followed by an inverting amplifier topology.

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Please keep in mind that I understand this circuit may be incorrect, I just built it as I had it pictured in my mind as the simplest way to illustrate my question.

In this case, how can I define the cutoff frequency of the filter, as well as the phase shift that the signal experiences? I know that the Low Pass filter delays the signal in 45º, and that the inverting OpAmp inverts the signal in 180º. Then, would the phase shift be -45º-180º=-225º?

Best Answer

To be clear and to protect against future edits, here is the circuit you show that this answer pertains to:

There is no low pass filter here. That is because the negative input of the opamp stays at 0 V during normal operation. The voltage across C2 doesn't change, so there is no current thru it, so there is no difference if it were removed.

With C2 removed, this is simple block with a gain of -1. It does have frequency limits over which it works, but those are not well defined. One limit is a result of the gain-bandwidth product of the opamp. However, that is usually only specified as a minimum value, with little guidance how high it might be. There are other low pass filters due to parasitic capacitance, but again, those are hard to quantify.

If you want a predictable low pass filter with a single dominant pole, then you need to add your own deliberate filter component, like a inductor or capacitor, that dominates stray and parasitic values.