A quick translation:
Generator has \$Z_g = 50\Omega\$ and 12 V. The line is loaded with an unknown RL. We observe we have a maximum of 8 V at 250 MHz and a minimum at 500 MHz.
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Solution: Asks for the dielectrical permitivity and the \$Z_o\$ of the line
$$Z_o = \sqrt{L/C} = 50\Omega$$
and for the dielectrical permitivity of the dielectric it is
$$Z_o = \sqrt{\frac{\epsilon_o \epsilon_r}{\mu_o \mu_r}}$$
$$Z_o = 120\pi \cdot \sqrt{1/3}$$
from there we get the dielectrical permitivity.
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This asks for the line length which is my initial question. Is wavelength same as the line length or am I wrong?
$$\lambda = \frac{v}{f} = 0.159 m$$
Thanks and sorry for my lack of English in Electrical Engineering subject.
Best Answer
Signal Velocity = \$v_s=\dfrac {c}{\sqrt{\epsilon _r}}\$
\$\lambda=\dfrac{v_s}{f}\$