I'm trying to get the value of \$V_o\$ in this circuit. Here's the circuit:
Using Superposition theorem:
So first, we remove the voltage source and replace it with a short circuit. Then we calculate \$V_o\$.
Second, we remove the 1A current source replace it with an open circuit, then we calculate \$V_o\$.
Third, we remove 2A current source and replace it with an open circuit, then we calculate \$V_o\$.
Finally, we should add the three values of \$V_o\$ that we got in each case and thus we get the final answer of the total \$V_o\$.
My problem is that I'm unable to calculate the value of \$V_o\$ in each case, what exactly should I do after removing the source to get \$V_o\$. Any help is much appreciated!
Best Answer
No, you pick a single source to use in your 1st analysis and, for ALL the other sources, you make them short (voltages) or open (current). That's how superposition works for each source. Then you add the individual voltages derived for each \$V_O\$ to produce the final value of \$V_O\$.
In other words:
Use one source with the others disabled then step and repeat for each source: -