Electrical – Laser driver current and temperature management

customlaser-driverModulationpwmtemperature

For a project I need to make a custom laser driver for a dot green laser module.

Below and here 1 you can find my design, the laser I've using now is a PLT5 510 OSRAM, the VSYS is 3,7 V DC from a Li-Ion battery.

The optical power output measured with this set-up are around 1.5 mW, I need to increase the optical power output around 10 times more. I can adjust the feedback current changing the value of the resistors.

If I increase the optical power output, the temperature of the module increase a lot, 90 degrees instead 35 degrees in the normal use.

How can I make a good regulation of the current of the laser module, and get almost 10 mW of optical power output, with a less temperature in the module?

I've no idea if I can use PWM to drive the laser and how to make this regulation, because the laser has a Feeback PIN and I'm thinking about the PWM can affect to the normal and properly running of the laser module.

Please can anybody help me?

Thanks in advance!

Driver laser module

Best Answer

You probably can't. And it has zero to do with how your circuit works.

First line from datasheet (seriously!!!):

• Optical output power (continuous wave): 10 mW (T case = 25 °C)

Acting as if you knew that and would be willing to stress your device beyond that:

The optical power output of this kind of lasers is, sufficiently above the lasing threshold, a linear function of the current flowing through the diode. See datasheet p.3.

So, to get 10x as much output power, you need to put in 10x as much current. Simple as that. Following said figure from said datasheet:

P/I curve and V/I curve

at ~40°C and ~1.5mW output, you're currently driving the device with 36 mA. With the right curve, you get a forward voltage of about 4.7 V, meaning your device is converting about 4.7 V· 36 mA = 0.17 W into heat.

15 mW is already out of the range of that curve, but let's extrapolate.

The slope of the power/current curve at 40 °C is roughly 0.3 mW/mA. You need around 14 mW of additional power, so that's about 46 mA more current, or (36+46) mA = 82 mA in total. Right chart tells us you'd have a forward voltage of ~ 5.2 V there. That means you're basically converting (nearly) 5.2 V * 82 mA = 0.43 W into heat here; that's 0.16 W more than you're currently doing.

The danger here is that you have a control loop that keeps the output constant. Now, when the temperature slowly rises, you'll need to push through more current to get the same output. That in turn will lead to more heat production, will lead to higher temperature, and will in turn lead to your control pushing through more power. That'll not end well for the diode.

conclusion

By far your best bet with this specific laser diode is to:

Actively cool the device, possibly with liquids, to keep its temperature as low as possible, so that you get the "better" P_out/I_in curve

Realistically, get a stronger laser diode. These might not be fun to hit your eye with.