antennaRF
I was reading up on parabolic reflector designs ,specifically the prime fed design and I can't seem to understand how this design works so well? Won't a major portion of the power reflected off the reflector be input to the feed thereby increasing the VSWR ? 
Also , would any reflector dish work with a feed . What would be the things apart from gain to keep in mind while designing a dish given a feed .
This antenna is a modified form of the Yagi-Uda antenna. A basic Yagi antenna consists of three sections. A reflector, a driven element and a director. This is illustrated here:
You can clearly see each of these basic elements in the antenna you have purchased. The reflector at the left of your image serves to increase the directivity of the antenna by focusing the beam pattern towards and along the axis of the smaller directors.
The driven element is the somewhat circular section in the middle that attaches to the Balun. This element actually conducts the signal down the attached fly lead.
The directors are the short parallel elements that extend away from the driven element. The width of the directors determines the frequency at which they enhance the directivity of the antenna. A wideband antenna has many different width, parallel elements. The spacing between the elements affects the phase and hence the beam pattern of the antenna.
Yagi's rely on the principles of phased arrays for the large directivity (apparent gain) that they offer. The antenna you have purchased has taken this principle even further with its triple boom design. The addition of more directors to the system with a phase difference in two axis allows greater manipulation of the beam pattern and directivity of the antenna. The net result is an increase in the level of the received signal.
No, you need to leave a hole through the solder mask under the inner feed and provide an isolated pad to solder it to. Anyway, if you feed from the inner feed, then the outer feed is going to become a stub that could cause some rather major reflection issues.
Best Answer
A dish has a radiating area of approximately that of a circle. That area being \$\frac{\pi D^2}{4}\$ = 0.785 sq metres for a diameter of 1 metre.
If the feed point is 10% the diameter of the dish then it will obscure an area of 0.00785 sq metres i.e. one-hundredth of the dish area.
So if 100 watts are being projected by the dish approximately 1 watt is wasted by the area of the feedpoint. That is a small price to pay even if that power were totally lost (and that isn't always the case).