I want to disconnect a negative of a battery connected to a DC motor using SSR relay.can we do it with ac load switching SSR
Electrical – Using SSR relay
dcmotorsolid-state-relay
Related Solutions
The snubber will be designed such that it passes minimal power at 50/60Hz, therefore the motor will not be "powered", although it may see a very small amount of passed power.
The motor's windings themselves will act as a shunt during shutdown - they can be viewed as purely-inductive, purely-resistive, or RL in parallel. Current will oscillate momentarily within the motor before dying to nothing (or near-nothing).
The real problem is that you have chosen the wrong opto-isolator. The 2964270 is a pull-up device. You needed something more like the 2966595 in a 5 V input version so that you could pull A2 on the customer's device down to 0 V. You seem to have realised this and added R1 but set it way too high.
The OPT-24DC/ 24DC/ 2 (used in the customer device) states that to get a logic 1 you need > 16 V across its input. It also states that typical current at 24 V will be 7 mA. (It will probably be only about 4 or 5 mA at 16 V.) To get it to turn on your R1 value needs to pull A2 to less than 8 V. A 560 Ω resistor will pass 14 mA at 8 V so it would suffice. Bear in mind that when your opto turns on that Q2 will connect that resistor to +24 V and the current through it will be 42 mA with power dissipation of > 1 W.
simulate this circuit – Schematic created using CircuitLab
Figure 1. A more complete schematic.
Best Answer
SSRs use one of several types of device to do the actual switchng. One for AC will probably use triacs. These will not switch off if used with DC the current through them has to go to 0 in order for them to switch off.
What you do use to do the switching depends on motor voltage and current and what you are driving it with. In most cases a N-channel Mosfet would be the core component.