Electrical – Waveguides question

waveguide

A rectangular waveguide with dimensions \$a=10cm, b=6cm\$ is filled with dielectric material with an unknown relative coefficient \$\epsilon_r\$. The guide is terminated by an unknown load. It is excited by \$TE_{3,0}\$ modes at a frequency of \$2.5GHz\$. How may I determine \$\epsilon_r\$?

I know the cutoff frequency is given by:

$$f=c\frac{\sqrt{(n/a)^2+(m/b)^2}}{2\sqrt{\epsilon_r}}$$

I am also told that the first minima are at \$s_a=5mm, s_b=30mm\$ away from the load.
I know that the distance between the minima is \$\lambda/2\$, hence \$\lambda=50mm\$. Does that mean that \$c/(f\sqrt{\epsilon_r})=50\$? Because if it is then I can easily find \$\epsilon_r\$ to be approx. 1.55. Is that correct?

Best Answer

of course standing wave minima was given thus $$\lambda /2 $$so you are almost correct ... calc error...

$$\epsilon_r = (\dfrac{c}{\lambda f })^2~~ \text{ so }~~\epsilon_r=5.76$$