the point is: what do you want to compare? of course the two graphs you obtain should have a similar shape, but it could be that you will need some arrangement if you need to compare the values.

I don't know what your friend meant with "energy", but he is absolutely right when he speaks about normalisation. Let's imagine you want to compare the sensisivity of the two accelerometer: you need to have the data belonging to the same interval. the output interval depends on several things like accelerometer itself, ADC resolution, maybe scale settings and so on. in that case, you should normalise on "output dynamic" or "output range".

If your problem is more general, let say is "what is the normalisation?", imagine the situation I described above, and suppose you have the data from the first accelerometer coming from a 10bit ADC, and from the second one coming from a 12 bit ADC.

The first bunch of data will belong to the [0,1023] inverval, the second one to the [0, 4095] interval. In this case, if we suppose that both accelerometers have the same sensitivity and max acceleration range, when the body is moved at 75% of his maximum acceleration the first one will give you 75% of 1023, the second one 75% of 4095...these two data represent the same acceleration but are clearly different.

To compare mathematically the two bunches of data, in this case, you should just make the ranges equal with some operation that is called "normalisation". In this case, you could simply use the range of the first accelerometer as "normalised range" and divide all the data coming from the second one by 4, or use float numbers and divide the first by 1023, the second by 4095 normalising to the normalised range [0, 1].

hope this helps
Cristiano

Is COM the common ground for Vs and X,Y,Z outputs?

Yes, the evaluation board schematic shows the output filter capacitors from X, Y, and Z to COM.

What is ST pin for? I couldn't figure out what it is used for?

Self test, check the datasheet, you probably don't need it.

Should the power supply be constant? Can I use a battery? The reason I
am asking these if I have 9V constant power supply and I use 3
resistors to make a voltage divider, would it be ok?

No, use a proper regulator. See this question.

How can I extend that 6-pin, 0.1 inch spaced header? Is there generic
plug name?

That is about as generic a termination as you can get. Find yourself something through hole with .1" pitch on your favorite distributor's website. Look at Molex and Amphenol for a locking header and connector.

## Best Answer

First of all, despite the initial paraphraph in Andy aka's answer, your use of 9.81 m/s^2 is correct (if not well explained): You correctly converted your sensor's output noise amplitude from voltage units to the corresponding noise amplitude in acceleration units. Where you seem to be stuck is how to make sense of it.

To use the output of your accelerometer, you will pass it through some kind of (likely digital) filter or other algorithm. After all, the direct output is an instantaneous acceleration where, as you calculated, the noise alone means any individual value on its own will typically be off by 4 mm/s^2 and hence larger than the deceleration due to the drag you are interested in. So how much can you lower this noise by making more than one measurement?

The most obvious thing would be to average measurements, but that may be more difficult than it sounds, unless you can guarantee that your sensor is always perfectly aligned with the motion of your satellite. However, it is something that can be calculated relatively easily, without referring to things you'll learn later in aerospace engineering. But since it should interest you, let me at least drop the keywords: I'm thinking about sensor fusion and Kalman filtering.

So let's hypothetically say you have one full orbit to determine your acceleration value (this won't work in practice due to sensor drift, see the next paragraph). Essentially, you will be integrating (or averaging) your sensor output. The noise level you will see depends on what the actual, frequency-dependent noise is after taking into account only the frequencies that pass through your (integrating or averaging) filter. Andy aka's answer tells you the answer for one specific case assuming you have white (frequency-independent) noise and a specific frequency cut-off value. A better prediction will take the frequency-dependence of the noise into account. Just remember to calculate in what makes physical sense, noise power (the squares of noise amplitude), and only convert to what makes sense to us electrical engineers after you're done calculating/filtering/integrating. That way you'll likely get the right result immediately and conveniently avoid having to ask "what is root-Hz, and how do you calculate with it." At sub-Hz frequencies, the frequency dependence of your noise will almost certainly be 1/f noise, and your accelerometer datasheet may actually list a value for it.

Now for the caveat: Your frequency range for using an entire orbit for averaging, sub-mHz, is so low that the noise will probably have an even worse frequency dependence than 1/f. Because it's just too slow to measure conveniently, engineers often invent other names for it, talking about drift instead. Of concern is both the kind of drift that a theoretical scientist might prefer to call some worse-than-1/f-noise and that induced by environmental factors like temperature changes. Have a look at what all of this does in your application (the relevant figures are likely specified in your accelerometer's datasheet as worst-case limits for temperature-output coupling and longterm drift). If you're clever, you may find ways to custom design an algorithm (or complicated nonlinear filter) that removes part of the drift by comparing "coming" and "going" parts of the orbit, or rotating the sensor to be in and then opposed to the direction of motion. At some point, knowing something about Kalman filters may help...