Electronic – Calculate power of an LTE Signal

lteRFspectrum analyzerspread-spectrumtelecommunications

I am looking for the formula to convert the power level of an OFDM RF signal to an absolute power level.
For example if I have my typical rectangular RF spectrum and the bandwidth of the signal is 10MHz, if my signal power needs to be 23dBm, what power do I need to measure on the plateau of the rectangular OFDM signal?

For example I saw a measurement function in a spectrum analyser where you could bring up markers and it would give an RF power level measured across that bandwidth, I remember seeing the waveform peak at about -20dBm but integrated across the bandwidth the power level came out to be around 1dBm.

I would like to know the formula. if I know the bandwidth of my OFDM signal and know what power level i need to reach, what level should I measure at the peak of my RF signal?

Best Answer

Assuming the power spectral density (watts per Hz) are constant then take the overall power of 23 dBm and convert it to real power: -

$$\text{real power} = 10^{\frac{23}{10}} = 200 \text{ mW} $$

Next divide that by bandwidth (10 MHz) to get power per Hz: -

$$ 20 \text{ nano watts per Hz}$$ $$ = -77 \text{ dBW per Hz}$$ $$ = -47 \text{ dBm per Hz}$$